if sinA= 3/4 calculate cosA and tanA
Answers
Answer:
Here is your answer buddy , written by giving spaces.
Step-by-step explanation:
Given, sinA=
4
3
⇒
DC
BC
=
4
3
⇒BC=3k and AC=4k
where k is the constant of proportionality.
By Pythagoras theorem, we have
AB
2
=AC
2
−BC
2
=(4k)
2
−(3k)
2
=7k
2
⇒AB=
7
k
So, cosA=
AC
AB
=
4k
7
k
=
4
7
And tanA=
AB
BC
=
7
k
3k
=
73
Answer:
hi friends
Step-by-step explanation:
sin A = 3/4
ie, sin A = opposite side/ hypotenuse
opposite side = 3
hypotenuse = 4
by Pythagoras theorem,
adjacent side^2 = hypotenuse^2 - opposite^2
= (4)^2 - (3)^2
= 16 - 9
= 5
so , cos A = adjacent side / hypotenuse
= 5/4
tan A = opposite side/adjacent side
= 3/5
hope this answer is helpful
thank u