Question

if sinA=3/4

find cosA and TanA​

Answer 1

$\huge{Refer To The Attachment}$

Answer 2

here is your answer mate.

$sin = \frac{3}{4} = \frac{p}{h}$

by pythagoras, we have :

${h}^{2} = {p}^{2} + {b}^{2}$

${4 }^{2} = {3}^{2} + {b}^{2}$

${b}^{2} = 16 - 9$

${b}^{2} = 7$

$b = \sqrt{7}$

we know that :

$cos = \frac{b}{h}$

therefore

$cos = \frac{ \sqrt{7} }{4}$

$tan = \frac{p}{b}$

$tan = \frac{3}{ \sqrt{7} }$