Question

if sinA=3/4, find cosA, tanA

Answer 1

sinA= 2/4
$\cos( \alpha ) = \sqrt{1 - \sin( { \alpha }^{2} ) } \\ = \sqrt{1 - 9 \div 16} \\ = \sqrt{7 \div 16} \\ = \sqrt{7} \div 4$
similarly by the equation tanA=sinA/cosA
you can find ur answer

Answer 2

Hey friend..!! here's your answer
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Hope this attachment will help you
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