if sina=3/4 find the value of cosa
Answers
Answered by
1
sin²a + cos²a = 1
therefore,
cos²a= 1- sin²a
= 1 - 9/16
= (16-9)/16
= 7/16
therefore, cos a= √7/4
therefore,
cos²a= 1- sin²a
= 1 - 9/16
= (16-9)/16
= 7/16
therefore, cos a= √7/4
Answered by
2
sinA=p/h
sinA=3/4
P=3
H=4
pythagoras th.
B²=H²-P²
B²=4²-3²
B²=16-9
B²=7
B=√7
cosA=B/H
cosA=√7/4
I hope it helps u
Mark as a Brilliant
sinA=3/4
P=3
H=4
pythagoras th.
B²=H²-P²
B²=4²-3²
B²=16-9
B²=7
B=√7
cosA=B/H
cosA=√7/4
I hope it helps u
Mark as a Brilliant
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