Question

If sinA =3/4,then calculate cosA and tanA​

Answer 1

Step-by-step explanation:

$\sin( a) = \frac{3}{4} \\ \sin ^{2} (a) + \cos^{2} (a) = 1 \\ = > (\frac{3}{4})^{2} + \cos^{2} (a) = 1 \\ = > \frac{9}{16} + \cos^{2} (a) = 1 \\ = > \cos^{2} (a) = 1 - \frac{9}{16} = \frac{16 - 9}{16} = \frac{7}{16} \\ = > \cos(a) = \sqrt{ \frac{7}{16} } = \frac{ \sqrt{7} }{4} \\ \\ \tan(a) = \frac{ \sin(a) }{ \cos(a) } = \frac{ \frac{3}{4} }{ \frac{ \sqrt{7} }{4} } = \frac{3}{ \sqrt{7} }$

Answer 2

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Here is the Solution...

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This question can be solve by two methods.

Both are in the Attachment.