if sinA=3/4,then cosA=
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Imagine a right-angled triangle ABC, with AB as the hypotenuse, 4, and CB as the altitude, 3. The base AC = (16–9)^0.5 = 7^0.5
sin A = CB/AB = 3/4
cos A = AC/AB = 7^0.5/4
Hope its helps and correct!!!!!
Mark it as brainliest!!!
sin A = CB/AB = 3/4
cos A = AC/AB = 7^0.5/4
Hope its helps and correct!!!!!
Mark it as brainliest!!!
Answered by
1
If sin A = 3/4 , which is P/ H so we know that
P = 4 and H= 4 .
Cos = B / H
B = √7
So
COS A = √7 / 4
P = 4 and H= 4 .
Cos = B / H
B = √7
So
COS A = √7 / 4
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