Question

if sinA=3/4,then cosA and cotA is​

Answer 1

WE KNOW THAT SIN = P/H

P = 3 , H =4

BY PYTHAGORAS THEORM

B = ROOT 7

AND

COS A = ROOT 7 / 4

COT A = COS A / SIN A

COT A = 3/ ROOT 7

Answer 2

Answer:

$\large{\underline{\boxed{\cos \text A = \dfrac{\sqrt{7}}{4}}}}$

$\large{\underline{\boxed{ \cot \text A = \dfrac{\sqrt{7}}{3}}}}$

Step-by-step explanation:

Given that ;

$\sin \text A =\dfrac{3}{4}$

We know that ;

$\sin \text A = \dfrac{ \text{ perpendicular}}{ \text{hypotenuse}}$

So, we get;

• Perpendicular = 3
• Hypotenuse = 4

Now, we need to find base;

$\text{Base} = \sqrt{ \text{h}^{2} - \text p^{2} } \\ \\ \text{Base} = \sqrt{4 {}^{2} - 3 {}^{2} } \\ \\ \text{Base} = \sqrt{16 - 9}\\ \\ \text{Base} = \sqrt{7}$

Now,

$\cos \text A = \frac{\text{Base}}{\text{Hypotenuse}} \\\\\cos \text A = \frac{\sqrt{7}}{4}\\\\\cot \text A = \frac{\text{Base}}{\text{Perpendicular}}\\\\\cot \text A = \frac{\sqrt{7}}{3}$