Question

if sinA =3/4, then find cosA,cosB​

Answer 1

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Step-by-step explanation:

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Answer 2

Answer:

Cos A = √5/4 and Cos B = 3/4

Step-by-step explanation:

SinA= p/h

sinA = 3/4 ( given)

let 'p' be 3x and 'h' be 4x

and 'b' =? ( to be calculated)

by Pythagoras theorem

h²= p²+b²

b²= h²-p²

b²= (4x)²-(3x)²

b²=(16x²-9x²)

b²= 5x²

b=√(5x²)

b= √5x

Now, Cos A= b/h

Cos A = √5x/4x

Cos A = √5/4

And Cos B = b/h

Cos B = 3x/4x

Cos B = 3/4

I hope it will be helpful to you