Question

if sinA =3/4 then sec A =? ​

Answer 1

sin A = 3/4 , hence cos A = root 7/4

therefore sec A = 4/root 7

please look at the image attached :)

Answer 2

secA = $\frac{4}{\sqrt{7} }$

• Sine and cosine are trigonometric functions of an angle in mathematics. In the context of a right triangle, the sine and cosine of an acute angle are defined as the ratio of the length of the side directly opposite the angle to the length of the longest side of the triangle (the hypotenuse), and the neighbouring leg's length to the hypotenuse, respectively.
• The definitions of sine and cosine can be expanded more broadly to include any real value in terms of the lengths of certain line segments in a unit circle. The sine and cosine can be extended to arbitrary positive and negative values as well as complex numbers according to more recent definitions that represent them as infinite series or as the solutions to certain differential equations.

Here, according to the given information, we are given that,

The value of sinA is $\frac{3}{4}$.

Now, we know that, sine of an angle refers to perpendicular upon hypotenuse.

This means that, the length of the perpendicular is 3 and the length of the hypotenuse is 4.

Then, by Pythagoras theorem, we get,

$4^{2} =3^{2} +base^{2}$

Or, Base = $\sqrt{7}$

Now, we know that, secant of an angle refers to  hypotenuse upon base

Then, we get, secA = $\frac{4}{\sqrt{7} }$

Hence, secA = $\frac{4}{\sqrt{7} }$

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