Question

If sina = 3/5
and A is acute find sin 2 A and cos 2A​

Answer 1

Answer: sin2A = 24/25

cos2A = 7/25

Step-by-step explanation:

sinA = 3/5

therefore

cosA = 4/5

now

sin2A = 2sinAcosA

sin2A = 2*3/5*4/5

sin2A = 24/25

cos2A = cos^2A - sin^2A

cos2A = 16/25 - 9/25

cos2A = 7/25

Answer 2

Answer:

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Step-by-step explanation:

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