if sinA=3/5 and cosB =9/41, 0<A<90° and - 90°<B<0 then sin(A-B) is equal to
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sinA= 3/5
cos A= √1-9/25 = 4/5
CosB = 9/41
SinB = -√1 - 81/1681 ( negative sign as sin is negative in -90 to 0)
SinB = -√1600/81 = -40/9
sin( A-B) = SINACOSB - COSA SINB
= 3/5 . 9/41 - 4/5. (-40/9)
= 27/205 + 160/45
cos A= √1-9/25 = 4/5
CosB = 9/41
SinB = -√1 - 81/1681 ( negative sign as sin is negative in -90 to 0)
SinB = -√1600/81 = -40/9
sin( A-B) = SINACOSB - COSA SINB
= 3/5 . 9/41 - 4/5. (-40/9)
= 27/205 + 160/45
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