Question

If sinA=3/5 find sec²A-tan²A
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Answer 1

Answer:

1

Step-by-step explanation:

Let perpendicular be p, hypotenuse be h, base be b

sin A = 3/5 = p/h

Therefore, base = √ 5*5 - 3*3 = √16 = 4

sec²A - tan²A = h/b*h/b - p/b*p/b

                      = 5/4*5/4 - 3/4*3/4

                      = 25/16 - 9/16

                      = 16/16 = 1

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