Question

if sinA=3/5, find the value of cosA-sinA/2cotA​

Answer 1

Step-by-step explanation:

sinA = 3/5 = perpendicular/hypotenuse

• Perpendicular = 3
• Hypotenuse = 5

Base = √(H² - P²) = √(25 - 9) = √16 = 4

Now we have

h = 5 , b = 4 , p = 3

• sin A = p/h = 3/5
• cos A = b/h = 4/5
• cot A = b/p = 4/3

=> (cosA - sinA)/2cotA

=> (4/5 - 3/5) / 2*4/3

=> 1/5 × 3/8

=> 3/40