Question

if sinA=3/5 then 3cosA+sinA=​

Answer 1

Answer:

given sin A = 3/5 = opp/hyp

we know that

(hyp) square =( adj) square +(opp)square

5 square=adj square + 3 square

25= adj square + 9

adj square= 25-9 =16

therefore adj side =4

then

cosA = adj/ hyp = 4/5

3cosA+sinA= 3*4/5+3/5

=12/5+3/5

= 15/5

=3