Math, asked by nandan2175, 11 months ago

if sinA=3/5,then find the value of cosA and tanA​

Answers

Answered by Robonaut
17

Sin A = 3/5

Cos A = 4/5

Tan A = Sin A / Cos A

= 3/5×5/4

= 3/4

You can obtain the value of Cos A by substituting the value of sin A in a right angled triangle then applying Pythagoras theorom.

Answered by prathmeshmadane004
25

Step-by-step explanation:

Given : sinA =3/5

Solution : sin^2A + Cos^2 A =

[3/5]^2 + cos ^2A = 1

9/25 + cos^2A = 1

cos^2A = 1-9/25

cos^2A = 25-9/25

cos^2A = 16/25 .......[Taking square root]

cosA = 4/5

TanA = sinA/cosA

tanA = 3/5/4/5

tanA = 3/4

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