Question

if SinA =3/5 then find the value of tanA

Answer 1

Sin A =P/H
3/5=P/H
B^2=H^2-P^2
B^2=5^2-3^2
B^2=25-9
B=4
TanA=P/B
TanA=3/4

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Answer 2

Given:

Sin A=3/5

To find:

The value of Tan A

Solution:

The value of Tan A is 3/4.

We can find the value by taking the given steps-

We know that $Sin^{2} A$+$Cos^{2} A$=1.

Using the above property, we can find the value of Cos A.

Sin A=3/5

On putting the values, we get

$(3/5)^{2}$+$Cos^{2} A$=1

9/25+$Cos^{2} A$=1

$Cos^{2} A$=1-9/25=(25-9)/25

$Cos^{2} A$=16/25

Cos A=4/5

Now, we know that Tan A=Sin A/Cos A

On putting the values,

Tan A=(3/5)/(4/5)

Tan A=3/4

Therefore, the value of Tan A is 3/4.