Math, asked by rameshsarupuru, 3 months ago


If sinA = 3/5,
then find the values of the following:

i) sin 3A
ii) cos 3A
iii) tan 3
iv) cot 3A​

Answers

Answered by priyankagadhval
3

Step-by-step explanation:

sin 3a = 3* 3/5

sin 3 a = 9/5

i think it is tan 3 a

then tan 3a= 1/ sin 3a

so tan3a = 1/9/5

tan3A=5/9

cos 3a= sin3a/tan 3a

cos 3a= 9/5/5/9

cos 3a=1

cot 3a = sin 3A/cos 3A

cot 3a= 9/5/1

cot 3a= 9/5

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