Question

If sinA=3/5,Then tanA=??

Answer 1

if sin A = 3/5

Sin A = perpendicular/hypotenuse

perpendicular = 3k

hypotenuse = 5k

Base
$= \sqrt{25 - 9} \\ \\ = 4k$
Tan A = perpendicular/Base

Tan A = 3/4

Answer 2

HEY DEAR ... ✌️

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Here's , Your Answer ...

=) Given ,
Sin A = 3 / 5

To find :- Tan A

We know ,

Sin = perpendicular / Hypotenuse

Sin A = 3 / 5  

Then , P = 3 & H = 5

Now , By using Pythagoras theorem ,

b^2 = (h)^2-(p)^2

b^2 = (5)^2-(3)^2

b^2 = 25-9

b = 4

Tan A = Perpendicular / Base

= 3/4 (answer)

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HOPE , IT HELPS ... ✌️