Question

If sinA = 3/5, then the value of ( tanA + SecA) ^2 is?
Answer it friends​

Answer 1

Step-by-step explanation:

sinA = 3/5

tanA = 3/4

secA=5/4

(3/4 + 5/4)²

=(2)²

=4

Answer 2

Answer:

(AC)^2=(AB)^2+(BC)^2

(5)^2=(3)^2+(BC)^2

25-9=(BC)^2

16= (BC)^2

root 16=BC

4=BC

TanA=opp =3

adj 4

secA= 1 =hyp =5

cosA adj 4

(TanA+secA)^2

(3 + 5 )^2

4 4

(8 )^2

4

(2)^2

4