If sina=3/5and a is in the first quadrant then find sin 2a
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Answer:
approach use formula SIN2A
Step-by-step explanation:
SIN2A IS 2SinAcosA
sinA =3/5 ---- 1point
CosA= 4/5 ----2point
SUBSTITUTE IN SIN2A ( REMEMBER IT IS IN QUADRANT 1 , THEREFORE ALL POSITIVE)
ANSWER IS 2 × 3/5 × 4/5
24/25
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