If sinA=34 calculate cosA and tanA
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Step-by-step explanation:
Given, sin A=3
4
=>BC = 3
DC= 4
=> BC = 3k and DC = 4k
where k is the constant of proportionality.
where k is the constant of proportionality.By Pythagoras theorem, we have
AB²= AC²---BC²= (4k²)-(3k²)= 7k²
=> AB=√7k
So, cosA= AB = √7k = √7
BC = 4k = 4
And tanA= BC = 3k = 3
AB= √7k= √7
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