Question

If sinA =3By4Calculate tan A

Answer 1

Given, SinA = 3/4

Sinθ = Perpendicular/Hypotenuse

Let there be a right angled triangle right angled at B

So, SinA = 3/4 = BC/AC

Let there a constant K such that BC = 3k and AC = 4k

So, by Pythagoras theorem

AB²+BC² = AC²

AB²+(3K)² = (4K)²

AB²+9K² = 16K²

So, AB² = 16K²-9K²

Therefore, AB = √7K

TanA = Perpendicular/Base

         = 3K/√7K

         = 3/√7

Hope it helps.

Thanks!!!