Question

If sinA=4/5 find the value of 4tan-5cosA/secA+4cotA

Answer 1

this is ur answer

Hope that this helps you

Answer 2

sinA=opposite side/hypotenuse=4/5
so,
O.S=4
HYP=5
according to Pythagoras theorem,adjacent side is 3
now
tanA=O.S/A.S=4/3
cosA=A.S/HYP=3/5
secA=5/3
cotA=3/4
substituting the values,
= {(4×(4/3)}-{5×(3/4)} / {5/3+(4×(3/4))}

= {(16/3)-(15/4)} / {(5/3)+(12/4)}

= { (64-45)/12} / { (20+36)/12 }

= (19/12) / (56/12)

$\frac{19}{12} \times \frac{12}{56}$
ans:
$\frac{19}{56}$