Math, asked by ayeasmin082, 2 months ago

If sinA =4/5 then tanA =?​

Answers

Answered by shyamkathir007
3

Answer:

tanA = 4/3

Step-by-step explanation:

sinA = 4/5 = opp/hypo

by Pythagoras theorem

adj= √(hypo)^2 - (opp)^2

adj= √25-16

adj=√9

adj=3

TanA= 4/3 = opp/adj

Answered by aryashekhardutta
3

Step-by-step explanation:

sin A = Height/Hypotenuse = 4/5

Therefore,

Height = 4

Hypotenuse = 5

To find base:-

4^{2} + b^{2}  = 5^{2} (Pythagoras theorem height^{2} + base^{2}  = hypotenuse^{2})

b^{2}  = 5^{2} - 4^{2} \\= b^{2}  = 25 - 16 = 9\\= b = \sqrt{9} \\= b = 3

tan A = Height/Base = 4/3 (Ans)

Note:-

Height is opposite side and Base is adjacent side for angle A.

Here is your answer. Hope it helps!

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