Question

If SinA=5/12, Find CosA and TanA​

Answer 1

Answer:

Cos A = $\dfrac{\sqrt{119} }{12}$

Tan A = $\dfrac{5}{\sqrt{119} }$

Step-by-step explanation:

Given:

• Sin A = $\dfrac{5}{12}$

To find:

• Value of Cos A and value of Tan A

Sin$\theta$ = $\dfrac{Opposite \ side}{Hypotenuse}$

Using pythogoras theorem:

Hypotenuse²=Opposite side²+ Adjacent side²

According to Sin A = $\dfrac{5}{12}$, value of opposite side is equal to 5 and hypotenuse is equal to 12

according to pythogoras theorem:

12² = 5² + Adjacent side²

144=25+Adjacent side²

Adjacent Side² = 144-25

Adjacent side² = 119

Adjacent side = $\sqrt{119}$

Cos A = $\dfrac{Adjacent \ side}{Hypotenuse}$

Cos A = $\dfrac{\sqrt{119} }{12}$

Tan A = $\dfrac{Opposite \ side}{Adjacent \ side}$

Tan A = $\dfrac{5}{\sqrt{119} }$

The value of Cos A is $\dfrac{\sqrt{119} }{12}$ and value of Tan A is $\dfrac{5}{\sqrt{119} }$

Answer 2

Answer:

Step-by-step explanation:

we have

$sin a = 5/12$

Therefore,

Opposite side  =  5

Hypotenuse                12

Assume Opposite side as 5cm and hypotenuse as 12cm.

Applying Pythagoras Theorem,

$12^{2} = 5^{2} + x^{2} \\144=25+x^{2} \\x^{2} =144-25\\x^{2} =119\\x=\sqrt{119}$

So adjacent side is $\sqrt{119}$ cm

So cos A = $\sqrt{119}$/12

and tan A = 5/$\sqrt{119}$