Question

if sinA = -5/13 cosB = 3/5 find sin (A+B) cos (A- B)​

Answer 1

Step-by-step explanation:

If sinA=2/3 and CosB=3/5 and . Find Sin(A+B), Cos(A+B), tan(A+B), Where A, B and A+B are positive acute angles

------

If sin(A) = 2/3, cos(A) = sqrt(5)/3

If cos(B) = 3/5, sin(B) = 4/5

====================================

sin(A+S) = sinA*cosB+cosA*sinB

=(2/3)(3/5)+(sqrt(5)/3)(4/5)

= 6/15 + 4sqrt(5)/25

etc.

==================

cos(A+B) = cos(A)cos(B)- sin(A)sin(B)

----

= (sqrt(5)/3)*(3/5) - (2/3)(4/5)

====

= (3sqrt(5)/15) - 8/15

----

etc.

=====================================

tan(A+B) = sin(A+B)/cos(A+B)

====================

thank you

thank youhope it helps

thank youhope it helps if find my answer useful then please like and and mark me as the brainliest and also if you want then you can follow me also.