Question

if sina=a^2-b^2/a^2+b^2,find cosA,tanA and secA​

Answer 1

Step-by-step explanation:

If sin@=a²-b²/a²+b²

Then ,by using pythagorus theorm we can find that base is 2ab

So, cos@=base / hypotenuse

cos@= 2ab/a²+b²

tan@ = perpendicular / base

tan @= a²-b²/2ab

sec@=1/cos@

sec@= a²+b²/ 2ab