Question

If sinA = a & secA = b then cotA will be ?
Answer this question with explanation.
Pleaseeeeeeeeeeeeeeeeeeeeeeeee ​

Answer 1

Answer:

Let ABC be a right angled △ right angled at B.

cotA=

15

8

Let AB=8x and BC will be 15x.

AC

2

=AB

2

+BC

2

⇒AC

2

=64x

2

+225x

2

⇒AC=

289x

2

=17x

⇒sinA=

AC

BC

=

17x

15x

=

17

15

⇒secA=

AB

AC

=

8x

17x

=

8

17

solution

Answer 2

Answer:

If sinA = a secA = b

then :

sec A = 1/cos A

cos A = 1/b

sinA = a cos A = 1/b

then

cot A = cos A / sin A

➡️➡️1/b / a

1 / ba