Question

If sinA=a/b find secA+tanA in terms of a and b

Answer 1

Answer:

sinA=a/b

cosA= √(1-sin²A)

cosA= √(1-a²/b²) = √(b²-a²)/b (denominator is b as √b²=b)

secA = 1/cosA = b/√(b²-a²)

tanA = sinA/cosA = a/b×b/√(b²-a²)

= a/√(b²-a²)

secA+tanA = b/√(b²-a²) + a/√(b²-a²)

= (b+a)/√(b+a)(b-a)

on rationalising, we get,

= √(b+a)/(b-a)