Question

If sinA=a/b,then find the value of tanA

Answer 1

sinA= a/b

we know {sinA}^2 +{cos A}^2=1
or, cosA={1-(sinA)^2}^(1÷2)
={1- (a/b)^2}^(1÷2)
so, tanA=sinA÷cosA
=(a/b)÷√{1-(a/b)^2}
simplifying we get

tanA= a÷√(b^2-a^2)

Answer 2

Hello !!!




Sin A = A/B = P / H




P = A and H = B



By Pythagoras theroem,


( H )² = ( B )² + ( P )²




( B )² = ( H )² - ( P )²


( B )² = ( b )² - ( a )²



B = ✓b² - a²


Therefore,


Tan A = P / B = a / ✓b² - a²




★ HOPE IT WILL HELP YOU ★