If sinA and cosA are zeroes of the polynomial mx^2-nx+1, what is the relation between m and n?
Answers
Answered by
2
sum of roots,=sina+ cosa=n/m::::::(1)
product =sinacosa =1/m
we know
(sina+cosa)^2=sin^2a+cos^2a +2sinacosa
(n/m)^2=1+2(1/m)
n^2/m^2=m+2/m
n^2=m(m+2)
n^2-m^2-2m=0...is the relationship between m and n
product =sinacosa =1/m
we know
(sina+cosa)^2=sin^2a+cos^2a +2sinacosa
(n/m)^2=1+2(1/m)
n^2/m^2=m+2/m
n^2=m(m+2)
n^2-m^2-2m=0...is the relationship between m and n
Similar questions