Question

if sinA = cos (A-18°), then the value of A is

Answer 1

HEYA!!
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Sin A = Cos ( A - 18° )

Cos ( 90 - A ) = Cos ( A - 18° )

[ Using Cos ( 90 - Ø ) = Sin Ø ]

We have,

90 - A = A - 18

90 + 18 = 2A

2A = 108

A = 108/2

A = 54°

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Answer 2

Hey frnz here is the solution.....

$\sin(a) = cos(a - 18) \\ cos(90 - a) = cos(a - 18) \\ 90 - a = a - 18 \\ 2a = 108 \\ a = 54$
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