Math, asked by sameeksha80, 1 year ago

If sinA=cos A, find the value of 2tan^2A -sec^2A+5

Answers

Answered by Anonymous
1
sin a = cos a

sin a = sin( 90 - a )

a = 90 - a

a + a = 90°

2a = 90°

a = 45° ------: [ 1 ]


Now, we get that value of angle a is 45°



Therefore :-

2 tan² a + sin² a - 1

= > 2 tan² 45° + sin² 45° - 1

= > 2 ( 1 ) + ( 1 / √2 )² - 1

= > 2 + 1 / 2 - 1

= > 2 - 1 + 1 / 2

= > 1 + 1 / 2

= > ( 2 + 1 ) / 2

= > 3 / 2




sameeksha80: thnx a lot !!!
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