If sinA = cos sq.45 .Find the value of tan A.
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1
tanA=0and sinA value is 0
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0
SinA=cos sq. 45
sinA=1/2
cos sq. A=1-sin sq. A
=1-1/4=3/4
cosA=(3/4)^1/2
tanA=sinA/cosA
=(1/2)/{(3/4)^1/2}
=(4/3)^1/2
sinA=1/2
cos sq. A=1-sin sq. A
=1-1/4=3/4
cosA=(3/4)^1/2
tanA=sinA/cosA
=(1/2)/{(3/4)^1/2}
=(4/3)^1/2
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