Question

if sinA=cosA 0°<A<90° then A is equal to can anyone explain and answer this​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$sin \: a = \: cos \: a \\ \implies \: \frac{sin \: a}{cos \: a} = 1 \\ \implies \: tan \: a \: = 1 \\ \implies \: a = {tan}^{ - 1} (1) \\ \implies \: a = {45}^{ \circ}$

Note :

$tan \: a \: = \frac{sin \: a}{cos \: a} \\ \\ tan \: {45}^{ \circ} = 1$