If sina + Cosa = 1, possible values of a will be?
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Step-by-step explanEq1:sin(A)+cos(A)=1=>a/c+b/c=1(given)
Eq2:a2+b2=c2(P.Theorem)
You may be wondering at this point how we can solve a system of 3 variables with 2 equations. Well, we can simply just fix one of the side lengths for convenience and solve for the other two. That is what I did in the above picture, setting a = 1.
Now we solve for b, c:
Eq1:a+b=c
b=c−1
Eq2:a2+b2=c2;
b2=c2−1
So, subbing c - 1 for b, we have:
(c−1)2=c2−1
c2−2c+1=c2−1
−2c+1=−1
2c=2=>c=1;b=c−1=0;a=1ation:
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