If sinA+cosA=√2cosA,show that,tan2A=1
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Answer:
tan 2A = 1
Step-by-step explanation:
=> sin A + cos A = root2 cos A
=> sin A = root2 cos A - cos A
=> sin A = cos A (root2 - 1)
=> sin A / cos A = root2 - 1
=> tan A = root2 - 1
NOW,
=> tan 2A = 2 tan A / 1 - tan^2 A
=> tan 2A = 2 (root2 - 1) / 1 - (root2 - 1)^2
=> tan 2A = 2 (root2 - 1) / 2 root2 - 2
=> tan 2A = 2 (root2 - 1) / 2 (root2 - 1)
=> tan 2A = 1
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