Question

If sinA: COSA = 3 : 4 then secA + COSECA is​

Answer 1

Answer:

sinA/cosA=3/4

(opp/hyp)/(adj/hyp)=3/4

opp/adj=3/4

tanA=3/4

so opp=3,adj=4,hyp=5(by Pythagoras theorem)

secA+cosecA

(hyp/adj)+(hyp/opp)

(5/4)+(5/3)

(15+20)/12

35/12 is the answer