If sinA + cosA = √3
find tanA + cotA
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Answered by
1
Answer:
answer is 1
Step-by-step explanation:
SinA+CosA=√3
squaring both side
(SinA+CosA)^2=3
(SinA)^2+(CosA)^2 + 2SinACosA = 3
Since (SinA)^2+(CosA)^2=1
2SinACosA = 2
SinACosA=1
now,
tanA + cotA = 1
SinA/CosA + CosA/SinA = 1
((SinA)^2+(CosA)^2)/SinACosA =1
1/SinACosA =1
SinACosA =1
hope it helps
Answered by
0
sinA+cosA = √3
squaring both sides
(sinA + cosA)² = 3
1+2sinAcosA = 3
2sinAcosA = 2
sinAcosA = 1
Now
tanA + cotA
=1/sinAcosA
=1/1
=1
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