if sinA + cosA =√3 prove that tanA + cotA=1
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Here is your answer MATE
sinA+cosA=√3
Squaring on both side we get,
(sinA+cosA)²=(√3)²
sin²A+cos²A+2sinAcosA =3
1+2sinAcosA =3
2sinAcosA=3-1
sinAcosA=2/2
sinAcosA=1 ------------(!)
tanA+cotA=1
sinA/cosA+cosA/sinA =1
sin²A+cos²A/sinAcosA=1
1/sinAcosA=1
sinAcosA=1 --------------(!!)
!=!!
thus tanA+cotA=1
I hope it will help you.....
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