If sina+cosa=7/5then find the value of sina-cosa=?
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Answered by
4
sq. both sides u get sin2a=49-25/25
sin2a=24/25
cos2a=...nikal loge.
cos2a=(cos a +Sina) (cosa-sina)
put value of cos 2a from above and put cosa+sina=7/5...from there u get cosa-sina
sin2a=24/25
cos2a=...nikal loge.
cos2a=(cos a +Sina) (cosa-sina)
put value of cos 2a from above and put cosa+sina=7/5...from there u get cosa-sina
Answered by
4
(Sina +cosa)^2+(sina-cosa)^2=2(sina^2+cosa^2)
(7/5)^2+(sina-cosa)^2=2(7/5*7/5)
(sina-cosa)^2=98/25-49/25
Sina -cosa=√49/25
Sina -cosa =7/5.
if my answer is helpful for you then please mark as brain liest
(7/5)^2+(sina-cosa)^2=2(7/5*7/5)
(sina-cosa)^2=98/25-49/25
Sina -cosa=√49/25
Sina -cosa =7/5.
if my answer is helpful for you then please mark as brain liest
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