if sinA+cosA=a,sinA-cosA=b,prove that a²+b²=2
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To prove : a²+b² = 2
=> (SinA-CosA) ² + (SinA-CosA) ²
=> Sin²A + Cos²A + 2sinA.cosA + sin²A h cos²A - 2sinA.cosA
=> 1 +1
=> 2
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