If sinA,cosA & tanA are in GP find the value of cos^3A + cos^2A
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cosa/sina=tana/cosa
cos^2a =tana×sina
cos^2a=sin^2a/cosa
cos^3a=sin^2a
cos^3a+cos^2a=sin^2a+cos2^a
cos^3a+cos^2a=1
cos^2a =tana×sina
cos^2a=sin^2a/cosa
cos^3a=sin^2a
cos^3a+cos^2a=sin^2a+cos2^a
cos^3a+cos^2a=1
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How did you solved?
Answered by
3
Answer:
1
Step-by-step explanation:
the equation that is applicable in gp is
b^2 = a*c
here we have cosA as b
therefore,
cos^2A = sinA*tanA
= sinA*sinA/cosA (writing tan as sinA/cosA)
we get :
cos^3A= sin^2A
thus,
substituting the value in the question , we get :
sin^2A + cos^2A = 1
thus
the answer is 1.
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