If sinA = cosA, find the value of 2tan^2A+sin^2A-1
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The answer of above question is given below.
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Answered by
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Given :-
sinA = cos A
sinA/cosA = 1
we know that
sinA/cosA = tan A
hence,
tan A = 1
, but we know that tan 45° = 1
hence,
A = 45°
2tan²A + sin²A -1
2tan²45° + sin²45 - 1
we know ,
tan²45° = 1 , sin²45° = 1/√2
hence ,
2(1)² + 2 × (1/√2)² - 1
2 + 1 - 1
= 2
∴ 2tan²A + sin²A -1 = 2
sinA = cos A
sinA/cosA = 1
we know that
sinA/cosA = tan A
hence,
tan A = 1
, but we know that tan 45° = 1
hence,
A = 45°
2tan²A + sin²A -1
2tan²45° + sin²45 - 1
we know ,
tan²45° = 1 , sin²45° = 1/√2
hence ,
2(1)² + 2 × (1/√2)² - 1
2 + 1 - 1
= 2
∴ 2tan²A + sin²A -1 = 2
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