If sinA= cosA find the value of 2tan^2A+sin^2A+1
Answers
Answered by
8
Given that,
sinA = cosA -----1equation
So,
cos(90 - A) = cosA
90 - A = A
90 = 2A
45 = A
Now,
2tan^2 A + sin^2 A + 1
2(sinA/cosA)^2 + sin^2 45° + 1
As both sin and cos are equal, sin/cos = 1
2(1)^2 + (1/√2)^2 + 1
2 + 1/2 + 1
(4 + 1 + 2)/2
7/2
I hope this will help you
(-:
sinA = cosA -----1equation
So,
cos(90 - A) = cosA
90 - A = A
90 = 2A
45 = A
Now,
2tan^2 A + sin^2 A + 1
2(sinA/cosA)^2 + sin^2 45° + 1
As both sin and cos are equal, sin/cos = 1
2(1)^2 + (1/√2)^2 + 1
2 + 1/2 + 1
(4 + 1 + 2)/2
7/2
I hope this will help you
(-:
Similar questions