Question

if sinA +cosA=p and sin³A + cos³A=q
what will be the answer

Answer 1

Hi Mate!!!

Sin³A + Cos³A = { Sin A + Cos A }³ - 3 [Sin A × Cos A] { Sin A + Cos A }


=>. q = p³ -3p [ Sin A × Cos A ]



{ Sin A + Cos A = p² -1 / 2 } put this value in

above equation


=>. q = p³ - 3p { p² - 1} / 2

=>. p³ -3p +2q =0


Have a nice time...

Answer 2

Hello dude

this is your answer:

sin³A+cos³A+3sinA×cosA

(sinA +cosA)=p³

=>q+3sin A×cos A(p) =p³

=>sinA+cosA= p ( sq on both sides )

=>sin²A+cos²A+2sinA-cosA=p²

=>2sinA×cosA =p²-1

=>sinA×cosA=p²-1/2

=>q+3(p²-1/2) ( p) = p³

=>q+3/2(p(p²-1)

=>3/2(p³-p²)=p³-q

=>3p³-3p=2p³+2q

=>3p³-2p³-3p +2q=0

=>p³-3p+2q =0

hope you understood my ans

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