Question

if sinA,cosA,tanA, are in the G.P ,then cot6A-cos2A​

Answer 1

Answer:

If sin(A),cos(A),tan(A) are in G.P., then which of the following option is correct cot6A−cot2A?

A)1

B)−1

C)0

D)2

Explanation:

Explanation:

Since sinA,cosAandtanA are in GP

cos2=sinAtanA

⇒cos2=sinAsinAcosA

⇒cos2Asin2A=secA

⇒cot2A=secA

⇒cot4A=sec2A

⇒cot4A=1+tan2A

⇒cot4A=1+1cot2A

⇒cot6A=cot2A+1

⇒cot6A−cot2A=1

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