If sinA = cosA then find the value of 2 tan square A - 2 sec square A + 5
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23
as we know cos x is equal to sin 90 - x
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Answered by
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sin A = cos A when A= 45°
so
2 tan^2 A - 2 sec^ 2 A +5
2(tan ^ 2 45° ) - 2 sec^2 45° +5
2(1)-2(√2)^2 + 5
2 - 2(2) +5
2-4+5
-2+5
=3
hope this helps you mate....
so
2 tan^2 A - 2 sec^ 2 A +5
2(tan ^ 2 45° ) - 2 sec^2 45° +5
2(1)-2(√2)^2 + 5
2 - 2(2) +5
2-4+5
-2+5
=3
hope this helps you mate....
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