If sinA=cosA then find the value of 2tan²A-2sec²A+5
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hey friend
it will be,
2(sin²A/COS²A)-2(1/cos²A)+5
if sinA=cosA
then,
2sin²A/sin²A-2(1/cos²A)+5
2-2(1/cos²A)+5
2{1-(1/cos²A)}+5 OR 2{1-sin²A}+5
hope it helps
thanks
it will be,
2(sin²A/COS²A)-2(1/cos²A)+5
if sinA=cosA
then,
2sin²A/sin²A-2(1/cos²A)+5
2-2(1/cos²A)+5
2{1-(1/cos²A)}+5 OR 2{1-sin²A}+5
hope it helps
thanks
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