If sinA=cosA then find value of 2tanA+cosA*cosA
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Heya!!!
Your answer is:
sinA = cosA
=> A = 45°
2tan45° + cos45° × cos45°
= 2 × 1 + √2/2 + √2/2
= 2 + 2√2/2
= 2 + √2
= √2( √2 + 1 )
Hope it helps you!!!
Cheers ☺☺
#foreverJungkook
Your answer is:
sinA = cosA
=> A = 45°
2tan45° + cos45° × cos45°
= 2 × 1 + √2/2 + √2/2
= 2 + 2√2/2
= 2 + √2
= √2( √2 + 1 )
Hope it helps you!!!
Cheers ☺☺
#foreverJungkook
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